NationStates Jolt Archive

This is where I will comment on various FT technologies, both my own and others. Anyone is welcome to ask questions about my tech here or ask me for their opinion on their tech.

There will also likely be quite a few heated discussions regarding tech here, so be warned.

And now without further ado, my first comment whihc is continued from this thread (http://forums2.jolt.co.uk/showthread.php?t=381646&page=3).

CorpSac

no you idiot, all things like novas, black holes etc are natraul things (thats what i ment by mother nature think outsidethe box for once its not hard), you dont understand much do you. when i sead man made thing i ment man made black holes, Tears in space bloody hell where you from, oh and wolf stop flaiming in my bloody storefront or atlest tell your stupid mate to stop it, thats the final warning.

Oh I'm sooo sorry I couldn't read your mind. :rolleyes:. It's your job to make sure others understand your tech, not to make vague statements and then expect others to divine your meaning. If someone misunderstands, it's your fault for not explaining it properly as the author, not the readers for failing to understand what you meant. It's not a hard concept, perhaps you should look into trying it out sometime.

Also my assesment was accurate based on your original statement

about 5Km above and below the planets and about 4Km from the 8th planet in the system, all the real barrier does is prevent anything thats not done by mother nature happening, since all things have a quntom sig its easy to pic out (natral is different to man made a hell of alot) this goes to magic to if mother nature dont cast it its a tamper from man and the Real barrior prevents it. (its annoying for me since it also mean that my FTL dont work). befor u cry godmod there people who have FTLi fields a 100ly's from there systems and so forth.

Look at the highlighted text. That's called an all inclusive statement. You said that anything that doesn't occur in nature is stopped from working, and that includes things like guns, internal combustion engines, computers, electrical generators, power plants, bicylces and hell even sharp rocks tied onto a stick. All of which is irrelevent anyway because if anything happens, it's because nature allows it to happen. So your barrier would do jack all anyway. So I'm not the one who doesn't understand anything here, you don't even understand your own bloody statements.

Gravity Weapons

Now this is one of my three big pet peeves with FT technology, "organic" technology and nanotech being the other two. The reason for this is fact that gravity is the weakest of all the fundamental forces, by many orders of magnitude. In particle interactions gravity is 10^37 times weaker than the electromagnetic force, for those who don't know scientific notation that's 10 trillion trillion trillion times weaker. Don't get me wrong, gravity can be a mighty powerful force, like when used to compress a cloud of interstellar gas into a star or to force a stellar core past neutron degeneracy to form a black hole. However all of those scenarios require amazingly huge amounts of mass. In terms of weapons, a starship just doesn't have enough mass, or equivalent energy, to produce any significant amount of gravity.

Let's take a look at a common form of a gravity weapon, the artificial black hole. I'll do four scenarios, one using the often given figure of "an event horizon the size of a small moon", one using a ten meter black hole radius, one using a starship mass of 5x10^11 kg or 500 million metric tons, and one using the mass of a missile (which is the most realistic scenario).

Scenario 1:

To determine the mass of a black hole from it's event horizon radius you need to solve for it from the equation

Rs = 2GM/c^2

Where "Rs" is the Schwarzschild Radius, or the radius of the event horizon, "G" is the Universal Gravitational Constant, "c" is the speed of light, and M is the mass of required. If we assume a small moon is half the diameter of the Moon, Rs would be 869,045.76 m.

We find the required mass "M", using the following,

M = [(Rs)(c^2)]/2G

Solving for "M" we get,

M = [(8.6904576x10^5)({3x10^8}^2)]/(2 x 6.673x10^-11)
M = 5.86x10^32 kg

Thus the required mass is 5.86x10^32 kg or 294.6 times the mass of the Sun. This is completely impossible for a starship, let alone a missile warhead, to generate.

Scenario 2:

A black hole with Rs = 10m.

M = [(Rs)(c^2)]/2G
M = [(10)({3x10^8}^2)]/(2 x 6.673x10^-11)
M = 6.74x10^27 kg

The required mass for this black hole is 6.74x10^27 kg, or 1128 times the mass of the Earth. This is again completely impossible.

Scenario 3:

I'll calculate the force on block of titanium with a mass of 4507 kg, an area of 1 meter^2 and a UTS of 900 MPa at a radius of 1 meter.

g = GM/r^2
g = (6.673x10^-11)(5x10^11)/ 1^2
g = 33.365 m/s^2

Fg = (g)(m)
Fg = (33.365)(4507)
Fg = 150 376.055 N

Pressure = Fg/area
Pressure = 150 376.055/ 1
Pressure = 150 376.055 Pa = .15 MPa

Thus using even a starship's mass to generate the weapon won't generate enough pressure to even damage modern day materials, let alone advance FT ones. The most may be a slight deviation in the targets trajectory.

Scenario 4:

The mass of the missile is 200,000 kg.

g = GM/r^2
g = (6.673x10^-11)(2x10^5)/ 1^2
g = 1.335x10^-5 m/s^2

Fg = (g)(m)
Fg = (1.335x10^-5)(4507)
Fg = .06 N

Pressure = Fg/area
Pressure = .06/ 1
Pressure = .06 Pa = 6x10^-8 MPa

The missile won't even be noticeable, let alone damaging. You'd be better off just ramming the missile into the ship as that would do more damage.


In conclusion, gravity weapons are infeasable as they would require absurd amounts of mass that no starship can carry to do any damage, and any reasonable mass does no damage at all.