Earagond
20-08-2004, 19:39
In response to the heavy number of nations who are researching and begging to build mechs,the Empire of Earagond has begun railgun research.In our theory,
B=NuI
B=Magnetic field strength (Teslas)
N=Number of turns in solenoid (1 in our case)
u=1.26x10^-6 (The magnetic permeability of free space, Henries/Meter)
I=Current through rails and projectile (Amperes)
LAYOUT OF THE RAILGUN (http://home.insightbb.com/~jmengel4/rail/simplerail.jpg)
Sooooooooooooooooooooooo
When a current I moves through a conductor of length L in the presence of a magnetic field B, the conductor experiences a force F according to equation 2.
(2) F=ILB
F=Force on conductor (projectile, in Newtons)
I=Current through rails and projectile (Amperes)
L=Length of rail separation (Meters)
B=Magnetic field strength (Teslas)
Aaaaaaaaaaaaaaaaaand
The direction of the force depends on the direction of the current through the projectile and the magnetic field since the force is truly a vector with direction dictated by the cross product of the vector quantities I and B. In Figure 1, the force is oriented down the rails, away from the power source.
Get it?
The info was taken from http://home.insightbb.com/~jmengel4/rail/rail-intro.html#rail
Anway,donations and help would be most appreciated :)
Also,we're trying for smaller rail guns,not giants. :)
B=NuI
B=Magnetic field strength (Teslas)
N=Number of turns in solenoid (1 in our case)
u=1.26x10^-6 (The magnetic permeability of free space, Henries/Meter)
I=Current through rails and projectile (Amperes)
LAYOUT OF THE RAILGUN (http://home.insightbb.com/~jmengel4/rail/simplerail.jpg)
Sooooooooooooooooooooooo
When a current I moves through a conductor of length L in the presence of a magnetic field B, the conductor experiences a force F according to equation 2.
(2) F=ILB
F=Force on conductor (projectile, in Newtons)
I=Current through rails and projectile (Amperes)
L=Length of rail separation (Meters)
B=Magnetic field strength (Teslas)
Aaaaaaaaaaaaaaaaaand
The direction of the force depends on the direction of the current through the projectile and the magnetic field since the force is truly a vector with direction dictated by the cross product of the vector quantities I and B. In Figure 1, the force is oriented down the rails, away from the power source.
Get it?
The info was taken from http://home.insightbb.com/~jmengel4/rail/rail-intro.html#rail
Anway,donations and help would be most appreciated :)
Also,we're trying for smaller rail guns,not giants. :)