Chemists/Physicists: You Are Needed!
New Burmesia
12-06-2006, 18:55
Okay, a quick question that I can't find out on the 'net. Basically, what does the speed of Photodissocation (say, a clorine molecule becoming two chlorine radicals) depend upon the frequency or intensity of radiation it is exposed to?
If it is intensity, my plan is le Buggered...NSers, your time is now!
Hydesland
12-06-2006, 19:00
In a spherical container, trasnform a chlorinemethylaqueus solution with a nicalcolbate powder using an endothermic displacement reaction catalyst. Using a particle insinerator measure the Photodissocation and use this formula:
(Pi/89)^78xE7F8GHI/10000= SinX79.0000001x Aslog/Mc^2/ADxK8(F)^UxC-K
There you will no exactly the rate of Photodissocation
Yes im bored....
Kilobugya
12-06-2006, 19:02
My memories of chemistry are a bit faded out, but I would say it depends on both.
My understanding is that it is both.
You need the correct frequency to excite the bond, but you need a high enough intensity to actually make the endevour worthwhile. You'll get the cleavage, no matter the intensity, but the higher the intensity, the more events that will occur.
Make sense?
Pantylvania
13-06-2006, 05:14
In most cases, you can simplify it to the answer Xun Kun gave. As long as the frequency is above the threshold, the rate is proportional to the intensity. If you want to cover extremely high intensities, extremely high frequencies, or frequencies just above the threshold, it gets more complicated.
If you meant the speed of a single interaction instead of the number of interactions per second, there's no intensity dependence and there might be some frequency dependence.