NationStates Jolt Archive

Some of you might already know it :

http://trunks.secondfoundation.org/files/psychic.swf

Try it, see if it works for you.
And if it does.... can somebody please explain to me why that works, before I go nuts here???

:headbang:

eep! :eek: Freaky.

I did it 5 times. It was correct 2 times. hmmm....

I did it five times, it got four of them.

I did it 5 times. It was correct 2 times. hmmm....

I figuered it out in the meantime. If it was correct only two time, you made a mistake :D

Foolproof. And amusing.

The symbols next to the numbers change with every try. But some numbers (0, 6, 9, 16 etc.) will have identical symbols in every go. These are the numbers that can be the results of the required calculations. None of the other numbers can be picked if you calculate correctly

I figuered it out in the meantime. If it was correct only two time, you made a mistake :D

Foolproof. And amusing.

no i didnt. *goes off to play with it some more*

The symbols next to the numbers change with every try. But some numbers (0, 6, 9, 16 etc.) will have identical symbols in every go. These are the numbers that can be the results of the required calculations. None of the other numbers can be picked if you calculate correctly

Beat me to it

the numbers are 9, 18, 27, 36, 45, 54, 63, 72 and 81

The symbols next to the numbers change with every try. But some numbers (0, 6, 9, 16 etc.) will have identical symbols in every go. These are the numbers that can be the results of the required calculations. None of the other numbers can be picked if you calculate correctly
clever... i bet the guy who made this went to the Maths Is Fun club.

i worked it out wrong first time, so i was like 'haha!! can't read my mind!'
and then i sorta had that taken out of me when it kept getting it right... :(

Multiples of nine. That's all.

Multiples of nine. That's all.

Nope. Try 90... :D

The symbols next to the numbers change with every try. But some numbers (0, 6, 9, 16 etc.) will have identical symbols in every go. These are the numbers that can be the results of the required calculations. None of the other numbers can be picked if you calculate correctly
Actually,
all the symbols stay the same, except for the ones corrisponding to:
Beat me to it
the numbers are 9, 18, 27, 36, 45, 54, 63, 72 and 81
Because, you select any two digit number (10a+b), then you add the digits together and subtract them from the original number (10a+b - (a+b)) giving 9a - or a number in the nine times table, as H-MW said.
The programme picks a symbol for these multiples every run-through, and that's what it shows when you click the ball.

Nope. Try 90... :D

90: 9+0=9
90-9=81 which is a multiple of 9

Nope. Try 90... :DYou can't get 90 from the method it gives.
90 -> 90 - 9 - 0 = 81
91 -> 91 - 9 - 1 = 81
etc...

This method will give a multiple for 9 for any number chosen. Whether it have one digit, or +5 digits. However, it won't ever give you the number 90.

The reason it gives multiples of 9 is to do with the base we use in our counting system (10). This method also works in any base, with the only number it not giving being (base)*(base-1). So in Hex the number you would not get is E0.

I tell a lie, this method does not really work in is binary. It's kinda stupid to say a formula will always give you a multiple of 1. And the multiple of 1 that it will never give is 10 because 2*1 is still 2 (the base).

9 x 10 = 90. Yet the number 90 will not bring up the correct symbol...

9 x 10 = 90. Yet the number 90 will not bring up the correct symbol...You can't get 90 using this method. 90 will give 81. 99 will give 81 and 100 will give 99.

9 x 10 = 90. Yet the number 90 will not bring up the correct symbol...
So it does. Or doesn't. It's almost a bug in it; you can't actually get 90 from a two-digit number, though, so it's moot (and possibly deliberate just to throw you off).

9 x 10 = 90. Yet the number 90 will not bring up the correct symbol...


i thought you were saying 90 wasnt a multiple of 9. sorry.



You can't get 90 from the method it gives.
90 -> 90 - 9 - 0 = 81
91 -> 91 - 9 - 1 = 81
But if it allowed you to go into 3 digit numbers, you could get 90 by using 100.

100: 10+0=10
100-10= 90

but then of course you get 90 by using any of the 3 digit numbers 100-109. and then you get 99 by using numbers 109-119 and so on, each time increasing by the next multiple of 9. Numbers are just neato

cool link CW

You can't get 90 using this method. 90 will give 81. 99 will give 81 and 100 will give 99.

Excatly my point. So it is some multiples of 9, but not all multiples of 9

Excatly my point. So it is some multiples of 9, but not all multiples of 9

I think they mean that by following the method and using only two digit numbers, you will always get a multiple of nine.The answer key gives solutions that arent possible to get by using only 2 digit numbers.

i have no idea what the hell is going on here.. whats suppose to happen?

i have no idea what the hell is going on here.. whats suppose to happen?


lol....did you click her link? If you do you will see the magic we speak of.:D

lol....did you click her link? If you do you will see the magic we speak of.:D
did, and now im confused. :(

did, and now im confused. :(

What is confusing you dear? If you do it several times...the ball should guess which number you were thinking each time.

What is confusing you dear? If you do it several times...the ball should guess which number you were thinking each time.

Well, the symbol rather. ;)

100: 10+0=10
100-10= 90

but then of course you get 90 by using any of the 3 digit numbers 100-109. and then you get 99 by using numbers greater than 109-119 and so on, each time increasing by the next multiple of 9. Numbers are just neatoI never thought of that. I just assumed that the it would be split into 3 separate digits. 1, 0 and 0. In which case you wouldn't be able to get 90.

Well, the symbol rather. ;)


yeah...what Cabra said.:D

i have not had nearly enough coffee yet apparantly.

too involved for me. I lost interest halfway through the first sentence.