NationStates Jolt Archive

I have seen a few of these on here lately..So in light of that, i have decided to make one of my own...here it is

1x=1

now figure out what x is equal too...


This is a tough one guys. i will grant immortality to those that get it right

x=1 :)

1 or -1

1 or -1
1

x=1 :)
What s/he said.

1 or -1
If it was x^2n where n is an integer, that would be true....

Well so far..you are all correct... you are all now immortals.. ( i do hope you all know this was a bs thread :D )

Well so far..you are all correct... you are all now immortals.. ( i do hope you all know this was a bs thread :D )
OK Zilam, what is the equation, in general form, of a line tangent to f(x)=x^(-1)+3x^2 at the point where x=6?

i knew it was, but i still had to try and good thing that i did because now iam imortial :D yahooooooooooo:D

The real answer is spam. As will soon be shown.

OK Zilam, what is the equation, in general form, of a line tangent to f(x)=x^(-1)+3x^2 at the point (6,649/6)?

y = 39849x - 264955995

EDIT: In standard form, 39849x - y = 264955995 if you want to pick nits :)

I got y=6648.9999x - 3684100.083. Could be wrong, may have missed a parenthesis or something in my calculator. Couldn't you just have x equal 2?

I got y=6648.9999x - 3684100.083. Could be wrong, may have missed a parenthesis or something in my calculator. Couldn't you just have x equal 2?

Well I did round those very large numbers. They were along the lines of 39849.9999 or so anyway.

And no, x is 6649 at the point Posi is interested in

x = (42 - 41)

now please give your answers in both polar and rectangular coordinates:D
[/insert evil laugh/]

Well I did round those very large numbers. They were along the lines of 39849.9999 or so anyway.

And no, x is 6649 at the point Posi is interested in
No I meant x is 6.

Well I did round those very large numbers. They were along the lines of 39849.9999 or so anyway.

And no, x is 6649 at the point Posi is interested in

Well, the point was 6,649/6 if I'm not mistaken, and I put that into the derivative, 6x - 1/(x^2), and came out with 6648.9999...yeah.


....

I stand corrected. He meant 6. In which case I now have y = 35.972x - 107.6


now please give your answers in both polar and rectangular coordinates
[/insert evil laugh/]


Never! I defy you!

No I meant x is 6.

What do you mean? Does x = 6649, 1108.16, or 6? You said, 'at the point (6649/6)'. I took that to mean (6649, 6) because a single value isn't a point ... which is it?

For those of you with higher math type education and know that Sqrt(-1)=i

1=1
1=Sqrt(1)
1=Sqrt((-1)(-1))
1=Sqrt(-1)Sqrt(-1)
1=i*i
1=i^2
1=-1

Thus, if 1x=1
and 1=-1
x could be 1 or -1.

(This can also prove that 2=0, so 1=0, and I never divided by 0. So there.)

For those of you with higher math type education and know that Sqrt(-1)=i

1=1
1=Sqrt(1)
1=Sqrt((-1)(-1))
1=Sqrt(-1)Sqrt(-1)
1=i*i
1=i^2
1=-1

Thus, if 1x=1
and 1=-1
x could be 1 or -1.

(This can also prove that 2=0, so 1=0, and I never divided by 0. So there.)
Generally there's something wrong with those proofs.

But I hate proofs so I'm not going to bother. :S

For those of you with higher math type education and know that Sqrt(-1)=i

1=1
1=Sqrt(1)
1=Sqrt((-1)(-1))
1=Sqrt(-1)Sqrt(-1)
1=i*i
1=i^2
1=-1

Thus, if 1x=1
and 1=-1
x could be 1 or -1.

(This can also prove that 2=0, so 1=0, and I never divided by 0. So there.)

Yeah, only you can't do that in a proof.

Kind of like saying
Sqrt(4) = Sqrt(4)
-2 = 2

This thread = Spam^2

What do you mean? Does x = 6649, 1108.16, or 6? You said, 'at the point (6649/6)'. I took that to mean (6649, 6) because a single value isn't a point ... which is it?
I mean (6, 108.1666r) or x=6, y=108.666r

I originally typed (6,649/6), where the "/" was used to indicate that y was a fraction.

x =

now please give your answers in both polar and rectangular coordinates:D
[/insert evil laugh/]

Assuming y=0 and z=0: (1,0,0) and (1,0,0) :p

polar: 1<0 (< is the angle symbol... too lazy to look it up on character map)

rectangular: 1 + j0 (j = i for us electrical types)

x = y - z where y = z + 1
x = y/z where y = z
x = y*z where y = 1/z or z = 1/y

x = j^4n, where n is any integer value

I don't need to answer as I am immortal already, so far, at any rate.

Fine, don't laugh at my amusing joke.

42!!!