NationStates Jolt Archive

I've been preparing for the LSAT in order to complete my application for law school. I've done a few practice runs, and have brought my score up from a 151 to a 159 so far, but the section that is literally KILLING me is the analytical reasoning section. Not only is it confusing as hell, but I end up getting through less than half in the time given. I have been really focussing on this section, but I can't seem to bring my score up yet.

But the questions are actually kind of fun! So I thought I'd wreck YOUR brains as well as my own on trying to figure them out!

A particular seafood restaurant serves dinner Tuesday through Sunday. The restaurant is closed on Monday. Five entrees—snapper, halibut, lobster, mahi mahi, and tuna—are served each week according to the following restrictions:

Halibut is served on three days each week, but never on Friday.
Lobster is served on one day each week.
Mahi mahi is served on three days each week, but never on consecutive days.
Halibut and snapper are both served on Saturday and Sunday.
Tuna is served five days each week.
No more than three different entrees are served on any given day.

1. On which of the following pairs of days could the restaurant's menu of entrees be identical?

(A) Friday and Sunday
(B) Tuesday and Wednesday
(C) Saturday and Sunday
(D) Wednesday and Friday
(E) Thursday and Friday

2. Which of the following is a complete and accurate list of the days on which halibut and lobster may both be served?

(A) Tuesday, Thursday
(B) Tuesday, Wednesday, Thursday
(C) Monday, Tuesday, Wednesday
(D) Tuesday, Wednesday, Thursday, Friday
(E) Tuesday, Wednesday, Thursday, Saturday

3. If mahi mahi is served on Saturday, it could be true that

(A) snapper and mahi mahi are both served on Sunday
(B) snapper and halibut are both served on Tuesday
(C) lobster and halibut are both served on Thursday
(D) tuna and snapper are both served on Saturday
(E) lobster and snapper are both served on Friday

4. Which of the following statements provides sufficient information to determine on which three days halibut is served?

(A) Mahi mahi and lobster are served on the same day.
(B) Lobster and snapper are both served on Tuesday.
(C) Tuna is served on Saturday, and lobster is served on Tuesday.
(D) Mahi mahi is served on Saturday, and snapper is served on all but one of the six days.
(E) Tuna is served on Sunday, and snapper is served on Tuesday and Thursday.

D, B, E, E. Next please.

Eight dogs in an obedience class are learning to follow two commands—"heel" and "stay." Each dog is either a shepherd, a retriever, or a terrier, and each of these three breeds is represented at least once among the group. All female dogs in the group are retrievers. The results of the first lesson are as follows:

At least two of the dogs have learned to follow the "heel" command, but not the "stay" command.
At least two of the dogs have learned to follow the "stay" command, but not the "heel" command.
At least one of the dogs has learned to follow both commands.
Among the eight dogs, only terriers have learned to follow the "stay" command.

5. Which of the following statements CANNOT be true?

(A) The group includes more females than males.
(B) The group includes fewer terriers than shepherds.
(C) The group includes more shepherds than retrievers.
(D) More of the dogs have learned to stay than to heel.
(E) More of the dogs have learned to heel than to stay.

6. If each dog has learned to follow at least one of the two commands, all of the following must true EXCEPT:

(A) All retrievers have learned to heel.
(B) All shepherds have learned to heel.
(C) All terriers have learned to stay.
(D) No retriever has learned to stay.
(E) No shepherd has learned to stay.

7. If four of the dogs are male and four of the dogs are female, all of the following must be true EXCEPT:

(A) One of the dogs is a shepherd.
(B) Four of the dogs are retrievers.
(C) Three of the dogs are terriers.
(D) Three of the dogs have learned to stay.
(E) Four of the dogs have learned to heel.

8. If the group includes more shepherds than terriers, the minimum number of male dogs among the group that have learned to heel is

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

9. If each dog has learned to follow at least one of the two commands, and if two of the dogs have learned to heel but not stay, it could be true that

(A) two of the dogs are female
(B) all of the dogs are male
(C) only one male dog has learned to heel
(D) one female dog has learned to stay
(E) two of the dogs are retrievers

D, B, E, E. Next please.
You suck.

Or are cheating. (found the page, did you?)

Either way, I hate you.

You suck.

Or are cheating. (found the page, did you?)

Either way, I hate you.

...page?

*looks on google*

EDIT- Ha! I have now. :p

But the questions are actually kind of fun! So I thought I'd wreck YOUR brains as well as my own on trying to figure them out!
The answer is to right down the account and writing number of a bank account with at least $2,000 in it. Works everytime for me.

Ewww.... logic games.

Have you tried putting the situation in the problem into a diagram?

Ewww.... logic games.

Have you tried putting the situation in the problem into a diagram?
You pretty much have to.

Ewww.... logic games.

Have you tried putting the situation in the problem into a diagram?

yeah, that's how you do it.

You can probably do it through algebra too, but sod that.

Five racing drivers, Alan, Bob, Chris, Don, and Eugene, enter into a contest that consists of 6 races. The results of all six races are listed below:

Bob always finishes ahead of Chris.
Alan finishes either first or last.
Eugene finishes either first or last.
There are no ties in any race.
Every driver finishes each race.

In each race, two points are awarded for a fifth place finish, four points for fourth, six points for third, eight points for second, and ten points for first.

If Eugene finishes two places ahead of Chris in the first race, all of the following will be true EXCEPT:

(A) Bob finishes ahead of Don.
(B) Chris finishes two places ahead of Alan.
(C) Don finishes fourth.
(D) Bob finishes immediately behind Eugene.
(E) Chris finishes ahead of Bob.

yeah, that's how you do it.

You can probably do it through algebra too, but sod that.
Did you really answer the questions in the first problem that easily? On your own? That makes me insane...I keep forgetting pieces of information, or assuming things, I suck at this!

(A) Bob finishes ahead of Don.
(B) Chris finishes two places ahead of Alan.
(C) Don finishes fourth.
(D) Bob finishes immediately behind Eugene.
(E) Chris finishes ahead of Bob.

E. That was easy.

Bob always finishes ahead of Chris....


...(E) Chris finishes ahead of Bob.

*sigh* A "read the question" one. I always hated those ones.

Did you really answer the questions in the first problem that easily? On your own? That makes me insane...I keep forgetting pieces of information, or assuming things, I suck at this!

I used to have trouble with them, but i practiced a lot, because they always cropped up on them damned standardised tests that I had to take during my last years of high school.

TBH, I think i got lucky with that one. I'm bound to screw up soon. :p

*sigh* A "read the question" one. I always hated those ones.

Yeah, it's like, "That can't be right! It was too easy!" *wastes 5 minutes on the question and can't get another answer* *finishes paper* *goes back to the question and remains uncertain...*

:p

E. That was easy.
Yeah, that one was actually pretty easy...I pulled that question from a questionable site...I've never seen anything that obvious on the LSAT.

Jane works at a fashion design company, and is having problems getting dressed for work. She refuses to wear any color combination that does not go well together as many of her clients may look down upon this.

She has two pairs of skirts, brown and blue; three blouses, white, sky blue, and gray; four pairs of stockings, red, black, brown, and blue; and two pairs of shoes, black and brown.

The blue skirt cannot be worn with red or brown stockings.
Gray does not go well with brown.
Black does not go well with brown.

1. If Jane wears black shoes she will not wear:

(A)red stockings.
(B)a blue skirt.
(C)a white blouse.
(D)blue stockings.
(E)a sky blue blouse.

2. If Jane is color blind and is unable to determine what outfits went well together, how many possible clothing combinations could she have?

(A)24
(B)32
(C)36
(D)44
(E)48

3. If Jane wears a brown skirt and a white blouse, she could:

(A)not wear blue stockings.
(B)not wear brown shoes.
(C)not wear black shoes.
(D)wear blue stockings.
(E)wear red stockings.

4. Jane buys a gray scarf. If she wears the new scarf, then she could:

(A)not wear blue stockings.
(B)not wear brown stockings.
(C)not wear black shoes.
(D)wear a white blouse.
(E)wear black stockings.

5. Jane will never wear:

(A)blue and red together.
(B)white and red together.
(C)gray and blue together.
(D)white and black together.
(E)white and red together.

Yeah, it's like, "That can't be right! It was too easy!" *wastes 5 minutes on the question and can't get another answer* *finishes paper* *goes back to the question and remains uncertain...*

:p
That's the thing exactly....so many times I think an answer is obvious, and it's wrong. So when an answer IS obvious, I assume it's wrong. ASSUMPTION IS A TERRIBLE THING!

Jane is a complete bitch.
Janes has clothes.

1. If Jane wears black shoes she will not wear:
(A)red stockings.


2. If Jane is color blind and is unable to determine what outfits went well together, how many possible clothing combinations could she have?
(E)48

3. If Jane wears a brown skirt and a white blouse, she could:
(C)not wear black shoes.

4. Jane buys a gray scarf. If she wears the new scarf, then she could:
(B)not wear brown stockings.

5. Jane will never wear:
(A)blue and red together.

Jane works at a fashion design company, and is having problems getting dressed for work. She refuses to wear any color combination that does not go well together as many of her clients may look down upon this.

She has two pairs of skirts, brown and blue; three blouses, white, sky blue, and gray; four pairs of stockings, red, black, brown, and blue; and two pairs of shoes, black and brown.

The blue skirt cannot be worn with red or brown stockings.
Gray does not go well with brown.
Black does not go well with brown.

1. If Jane wears black shoes she will not wear:

(A)red stockings.
(B)a blue skirt.
(C)a white blouse.
(D)blue stockings.
(E)a sky blue blouse.

2. If Jane is color blind and is unable to determine what outfits went well together, how many possible clothing combinations could she have?

(A)24
(B)32
(C)36
(D)44
(E)48

3. If Jane wears a brown skirt and a white blouse, she could:

(A)not wear blue stockings.
(B)not wear brown shoes.
(C)not wear black shoes.
(D)wear blue stockings.
(E)wear red stockings.

4. Jane buys a gray scarf. If she wears the new scarf, then she could:

(A)not wear blue stockings.
(B)not wear brown stockings.
(C)not wear black shoes.
(D)wear a white blouse.
(E)wear black stockings.

5. Jane will never wear:

(A)blue and red together.
(B)white and red together.
(C)gray and blue together.
(D)white and black together.
(E)white and red together.


A, E (fixed it), C, B, A

Meh...5am logic puzzles...they hurts my brain

A, E (fixed it), C, B, A

Meh...5am logic puzzles...they hurts my brain
Says the genius who did the first one in like two minutes. I haven't even taken a crack at this one yet. I'm going to go offline for a bit, while I update my other computer, and do the Jane one. I wonder if Dick ever enters into the equation...?

Says the genius who did the first one in like two minutes. I haven't even taken a crack at this one yet. I'm going to go offline for a bit, while I update my other computer, and do the Jane one. I wonder if Dick ever enters into the equation...?

Heh; genius, eh?

I wouldn't be surprised if I screwed at least one of those answers up, though. I didn't use a diagram.

Heh; genius, eh?

I wouldn't be surprised if I screwed that one up, though. I didn't use a diagram.
I got the same answers, through 5 was almost entirely guess work. I managed to eliminate a couple options, and then aribitrarily decided that the letter A was more fun than C or D.

Heh; genius, eh?

I wouldn't be surprised if I screwed at least one of those answers up, though. I didn't use a diagram.
You know, rubbing it in by being 'modest', then throwing in how you are able to do something this complicated in your head, just makes me want to hunt you down and eat your brain.

I got the same answers, through 5 was almost entirely guess work. I managed to eliminate a couple options, and then aribitrarily decided that the letter A was more fun than C or D.
I can definitely say 5 is A.

You know, rubbing it in by being 'modest', then throwing in how you are able to do something this complicated in your head, just makes me want to hunt you down and eat your brain.
Hmm...maybe you're working it out differently to me...the way i'm doing it, it seems pretty straightforward.

Example being question 1...if she's wearing black shoes, she can't wear the brown skirt. But if she wears the blue skirt, she can't wear red stockings. Hence the answer is A.

EDIT, actually, looking back, that was a really easy one.

Q3 is easy, brown can't go with black.

And Q4; grey can't go with brown.

Q5, the only red is the stockings, and the only other blue is the skirt. Thus she can't wear blue and red together.

I can NOT figure out why Q2 is 48 and not 44. I just can't. :( I thought you would multiply the number of total clothing items (11) by the total number of categories (4).

I can NOT figure out why Q2 is 48 and not 44. I just can't. :( I thought you would multiply the number of total clothing items (11) by the total number of categories (4).

two skirts. three different blouse combinations for each of these. four pairs of stockings for each of these. and finally, each of these results has two shoe possibilities.

2*3*4*2=48

I thought I'd wreck YOUR brains as well as my own on trying to figure them out!
Forget it! I never was good with that section either, and now I don't have to take those sorts of tests anymore, so MEH! :D

two skirts. three different blouse combinations for each of these. four pairs of stockings for each of these. and finally, each of these results has two shoe possibilities.

2*3*4*2=48
I frickin' suck:( That is so easy.:headbang:

I frickin' suck:( That is so easy.:headbang:

Hehe.

Can I take over your teaching job when you quit?

:p