NationStates Jolt Archive

I am making this thread so people can NS can post homework problems for others to solve for them...this is completely unrelated to the fact that I have a problem for you to solve.

Anyways...here is my problem.


Express without fractions, using negative exponents if needed:

x to the power of a

Divided by..

x to the power of a - 7

If for some reason you would like to see the equation with superscripts then here it is for download.

Express without fractions, using negative exponents if needed:

x to the power of a

Divided by..

x to the power of a - 7

x^a/x^(a-7)

That it?

Anyways if it is....

then the answer is x^7 (x to the power of 7)

You arrive at this by stating that x^a/x^(a-7) = x^(a-(a-7))

Thus x^7

Seems to simple actually, I'm probably missing something.

That's what I got though.

(x^a)
(x^[a-7])

is the same as x^(a-[a-7]) or x^7

I am making this thread so people can NS can post homework problems for others to solve for them...this is completely unrelated to the fact that I have a problem for you to solve.

Anyways...here is my problem.


Express without fractions, using negative exponents if needed:

x to the power of a

Divided by..

x to the power of a - 7

If for some reason you would like to see the equation with superscripts then here it is for download.

x^7

x^a/x^(a-7)= x^(a -(a-7))

X^7th.

Yeah.


*dies*

Well it looks like we solved that one pretty well.

I was going to say something about denominators being inverses, but I see you all have it figured out.

Your question has been answered rather thoroughly :P

Anyways, I doubt anyone here knows much about Italian culture... but in case anyone does....

My assignment for Italian class is ... and I quote

"You are returning from a semester-abroad program in Italy, and you have been asked to write a short summary of your experience. Write a paragraph telling where you studied, what courses you took, what the program was like, where you lived, and how you liked this particular place. Use your imagination for the details of your description."

Now I'd rather NOT make everything up, so it'd be nice if someone on here who is acquainted with Italian culture could give me a city and some generalities of what things are like there....

And if you happen to speak Italian some sentences I could throw into the paragraph would be nice :) Hehehe

First Off...Thank you to all that helped me...

Second off: Although i can't help with the experience...you can always use.

http://www.dictionary.com for the translator.

May I torture you with some math?

1. For f(x), (a) simplify y = (-2x + 7)/(x^2 - 2) and (b) solve for f(a^4)

2. Then, (a) find the inverse function (label as function 'g'). (b) Use that to solve for g(a^-2).

That was a homework question for tonight. I solved it, but I just want to see how many here can. Note: I'm a grade 11 student with a 94% average. 97% in Math.

[edit:] Wow, I was reading this right after I wrote it. http://forums2.jolt.co.uk/showthread.php?t=360810&page=2&pp=15 It's the second post down that's funny!

Heh too lazy to do it out, but I think I remember the exact same problem...

Do you by any chance happen to live in Ontario?

I'm in grade 11 right now, but I'm taking grade 12 math (I did grade 11 math last year).

Hmmmm sorta stuff we are doing right now....

Factor x^3+y^3

Or....

For f(x) = x^3+2x^2+10, find the derivative.

Yea I'm in Ontario, U math at a Catholic school. I can't wait 'till I do that stuff next year! Are you taking Calculus or Descreet?

Ah, I'm in a public school, but I guess the general curriculum is still pretty similar.

What city if I may ask?

Burlington, you?

Hamilton lol.

I live pretty close to you actually... well not really, but close for someone you find on the internet.

Yea.

yeah yeah...i'm lazy and pathetic...bleh, just please help ^^;


If 3y^2 - 3x + 5y= x- y Find x = f(y)




Given f(x) = 12/x, find f(4) + f(6) - f(2)


Dang functions....

On another note...why do i have the feeling i'm probaly going to be the only using this :headbang:

bump...

*bumps and trips?*

I developed a deep hatred of maths at A-Level, this thread is making me feel ill, and didnt it come back and bit me in the arse.

yeah yeah...i'm lazy and pathetic...bleh, just please help ^^;


If 3y^2 - 3x + 5y= x- y Find x = f(y)




Given f(x) = 12/x, find f(4) + f(6) - f(2)


Dang functions....

On another note...why do i have the feeling i'm probaly going to be the only using this :headbang:

If you can, get all of the x on one side of the = and all the y on the other.

Note: those are seperate equations...

and i dont understand what to do.. X_X

Anybody want to write a 7 page definition essay for me? MLA format...double spaced....non-specific topic (doesn't matter, just anything). Come on...it'll be fun :D

You can find premade essays on the internet.

www.thespark.com or was it www.sparknotes.com ?

either way...

yeah yeah...i'm lazy and pathetic...bleh, just please help ^^;


If 3y^2 - 3x + 5y= x- y Find x = f(y)




Given f(x) = 12/x, find f(4) + f(6) - f(2)


Dang functions....

On another note...why do i have the feeling i'm probaly going to be the only using this :headbang:

3y^2-3x+5y=x-y
3y^2+6y=-2x
2x=-3y^2-6y
x=(-3y^2)/2-3y

err...don;t you mean 4x?

Change negative 3x to positive when moving to other side..and you'll get x = 3x getting 4x, but thanx for first one i guess? It is right...right?

err...don;t you mean 4x?

Change negative 3x to positive when moving to other side..and you'll get x = 3x getting 4x, but thanx for first one i guess? It is right...right?

yes you are right
Sorry its been a looooong day
:headbang:

3y^2-3x+5y=x-y
3y^2+6y=-2x
2x=-3y^2-6y
x=(-3y^2)/2-3y


wrong...1x plus 3x equals 4x, not -2x. simple mistake.

3y^2+6y=4x
x=(3y^2+6y)/4 = (3/4)y^2 + (3/2)y = (3/4)(y)(y+2)

Anyone know anything about comparing utilitarianism and religious belief in regard to environmental ethics?

err...don;t you mean 4x?

Change negative 3x to positive when moving to other side..and you'll get x = 3x getting 4x, but thanx for first one i guess? It is right...right?

Well the way you say it may be more muddled than your understanding. You do move it like that but "x = 3x" is incorrect. Well I think you understand. Now do the same for y, and then reduce one side of the equation to simply x ... that is, x^1 + 0, which = x. What you will then have on the other side of the equation is equal to f(x).

As for the second one, just plug the numbers in the parentheses into the equation for f(x), one by one, and calculate their values. Now it's just streight arithmatic.

Teach me Hebrew and I'll teach you algebra, trig and calculus... deal? ;)

Sure... What words do you want to know? Generic Swears? Sentences? Pick-Up Lines? Slang?

Given f(x) = 12/x, find f(4) + f(6) - f(2)


y = 12/(4) + 12/(6) - 12/(2)
y = 3 + 2 + 6
y = 11

Oooh! I want to learn Hebrew too! It's so r0x0rz! But I like the 2nd millenium reconstructed pronunciation found here: www.omniglot.com/writing/hebrew.htm

y = 12/(4) + 12/(6) - 12/(2)
y = 3 + 2 + 6
y = 11

silly canadians. '-' is not '+' and your bacon is not bacon, it's ham.
y = 3 + 2 - 6 = -1

Oops! Damn I hate when I do that!

Haha.

P.S. I hate Canadian bacon! Lol...

Oh all of it.

Anyway the first thing you probably already realize about function notation is that the perentheses do not work the way that they do in other equations. In fact, you may wish to adopt the practice of using brackets for normal calculations, such as:

f(x) = 3y[y-2]/6

This will help avoid the natural confusion. It may seem like an easily overcome confusion, but for a person with numeraphobia it creates an unconscious impediment to understanding the equation as a whole.

Also, think of the entirety of all mathematics as a pyramid, with simple addition and subtraction as the very base level. All upper levels build on the same principles as the lower ones, only with more complex rules. If the initial foundation of a pyramid is shakey and not well founded, it is very hard to build upon it. So I recommend that you review all of your basic arithmatic; get to know it intimately, practice doing it in your head, perhaps visualizing the addition and multiplication tables. I know this seems redundent and that you already know this stuff, but the easier it is to do it without paper or a calculator, the easier it will be to understand the higher levels.

I make this topic for people to abuse...yet nobody uses it...

anyways new question :D

There is a 3-sided pyramid Note that every level of the pyramid is 2 cm high.

For some reason a bunch of architects decide to build a 3 sided pyramid out of marble (the ones you play with LOL) If each level is 2 centimeters high. How many centimeters tall can the pyramid get?

Thank you to all that help my laziness. :)

*those rolling thingies you see in western floats by....*

*those rolling thingies you see in western floats by....*

tumble weeds lol

I make this topic for people to abuse...yet nobody uses it...

anyways new question :D

There is a 3-sided pyramid Note that every level of the pyramid is 2 cm high.

For some reason a bunch of architects decide to build a 3 sided pyramid out of marble (the ones you play with LOL) If each level is 2 centimeters high. How many centimeters tall can the pyramid get?

Thank you to all that help my laziness. :)

If by "every level is 2 cm high" you mean that the appex of each side of the pyramid is 2 cm from the nearest point on the ground, the the answer is "2 cm". :) Does that help?

Otherwise perhaps you mean that each side is 2 cm from the midpoint of its base to its appex, along its surface? If you do not know the width of the base the question cannot be answered. Or else do you actually mean levels, like, the strata of rectangular-edged stones that pyramidal buildings are typically built as? I really doubt you mean that, but we would really need to know how many levels there are, wouldn't we?

Perhaps you mean that each side is a 2 cm equilateral triangle. This makes the most sense.

But you know what? Nobody can do your homework for you. All they can do is tell you the answers. And then your homework has not been done

But I will try to start you out: Each side is an equilateral triangle, so they are equiangular too, and you should easily be able to calculate their angles. Break the triangle(s) into two right triangles (each). You should have in your notes or in your books the formula for the ratios of the sides of a "30-60-90" triangle, &/or the pythagorian theorum, so you can calculate the length of the centerline (top to base) of each side.

Now what looks hard is figuring out the distance from the base of the centerline of each side to the center of the area of the base of the pyramid. But by taking one side and drawing the other two centerlines (making like an asterix * where they cross), you can break the triangle down into six "30-60-90" triangles, three identicle and three their mirror images. Using the fact that you know three of the angles and the length of one of the sides, you can get the lengths of other two sides, the one you want being the length from the center of the base of the pyramid to the base of each centerline.

Now you have two of the three lengths of the triangle described by the centerline of each side of the pyramid as one side,h the distance from the base of that centerline to the center of the pyramid's base as the second, and the distance from the center of the base to the top - the pyramid's hight, as the third. You don't know that last distance but you do know that it meets the lines from the bases of the centerlines at right angles.

Now use pythagores' theorum to find the hight.