Need Math Help
Superpower07
31-08-2004, 14:41
I need help simplifying this:
[p^(2m-5) - q^(m+3)][p^m - 2p^(m+1)q^(m+1) + q^3)]
LordaeronII
31-08-2004, 14:52
This isn't answering your question... but curious, what level math is that? (Grade 11, grade 12, 1st year university, etc. etc.)
Just curious because I'm pretty good at math for my age and I don't have a damn clue how to solve it (well I might be able to work something out if I sat here for half an hour, but you know what I mean)
Superpower07
31-08-2004, 14:56
This isn't answering your question... but curious, what level math is that? (Grade 11, grade 12, 1st year university, etc. etc.)
It's either Algebra I or II (10th-grade level at my school).
Gaeltach
31-08-2004, 14:57
Give me a bit and I'll take a stab at it. Math isn't my strongest subject, but this doesn't look too terribly difficult.
That said...anyone here good with Calc II?
just looking at it, you need to multiply each of the 2 terms in the first part by each of the 3 terms in the 2nd part (obviously), giving you 6 terms total. when you multiply two like variables, you add their powers. so p^(2m-5) times p^m would become p^(2m-5+m) or p^3m-5.
maybe when you multiply everything out you can cancel some things out and it will be a simple equation, im not sure, i havent carried it all the way out. good luck. :)
Pacem II
31-08-2004, 15:10
2p^(m+1)q^(m+1)
Are you missing a + or - here, or should we multiply 2p^(m+1) with q^(m+1)?
Superpower07
31-08-2004, 15:25
2p^(m+1)q^(m+1)
Are you missing a + or - here, or should we multiply 2p^(m+1) with q^(m+1)?
You're supposed to multiply them
Unspecified Paradise
31-08-2004, 16:31
maybe when you multiply everything out you can cancel some things out and it will be a simple equation
Unlikely, since it's not an equation at all (no "equals" sign, dead giveaway).
I'd simplify this for you, but it's been a long day and I've got enough maths to correct already.
Unlikely, since it's not an equation at all (no "equals" sign, dead giveaway).
I'd simplify this for you, but it's been a long day and I've got enough maths to correct already.
ah. i meant to say polynomial. i dont where i pulled equation, my mistake. and ive only been out of college for 3 months...
Superpower07
31-08-2004, 16:47
Could some1 *please* simplify this for me??
Demonic Gophers
31-08-2004, 17:26
Probably, but that doesn't mean anyone actually will...
I'd give it a try, but I don't have time.
Druthulhu
31-08-2004, 18:01
Unless I made an error at some step, I think the simplest form is:
(p^(3m+5)) - 2(p^(3m-4))(q^(m+1)) + 2(p^(m+1))(q^(2m+4)) - (p^m)(q^(m+3))
It could maybe be broken down further but that's all I'm willing to do right now.
Druthulhu
31-08-2004, 18:04
Oh well this one stands out:
(p^m)[(p^(2m+5)) - 2(p^(2m-4))(q^(m+1)) + 2p(q^(2m+4)) - (q^(m+3))]
Superpower07
31-08-2004, 18:05
AHHHHHH! Thanks for the help tho
Gaeltach
31-08-2004, 18:07
Oh well this one stands out:
(p^m)[(p^(2m+5)) - 2(p^(2m-4))(q^(m+1)) + 2p(q^(2m+4)) - (q^(m+3))]
Yeah, that's what I got. So unless you wanna take any wierd roots...
Is there any stipulation saying (p != q)?