Nova Hope
06-08-2004, 12:54
OOC:
I have to warn you the following is a lot of loose scribbling on my part. I was hoping any of you rail gun enthusiasts out there who have a penchant for physics might tell me what you think. If I don’t get to much flak out of character then I’ll RP the development and eventual launch of my fully automatic mini-rail gun.
The purpose of this weapon is more physiological then anything but don’t kid yourself with enough ammunition this thing will kick your ass. It’s a next step against missile shields, but as it stands its vulnerability to anti satellite warfare makes it a first strike weapon only. But again if you can put a missile shield up over your country I can put on my satellite. Thoughts? Comments?
(7) v(muz)=(2DF/m)^.5=(2DILB/m)^.5=I(2DLu/m)^.5
v(muz)=Muzzle velocity (Meters/Second)
D=Length of rails (Meters)
F=Force applied (Newtons)
m=Mass of projectile (Kilograms)
I=Current through projectile (Amperes)
L=Width between rails (Meters)
B=Magnetic field strength (Teslas)
u=1.26x10^-6 (The magnetic permeability of free space, Henries/Meter)
Mine:
v(muz)= I(2DLu/m)^.5
v(muz)= I(2D(.5m)(1.26*10^-6)/(455kg)^.5
My variable length of the rails D
Current through projectile I
set D to 200m
set I to 100000000 amps
v(muz)=(100,000,000 amps)(2(200m)(.5m)(1.26*10^-6)/(455))^.5
v(muz)=74,420.84m/s
v(muz)=74.42084km/s
Bullet .5m diametre
.065m^3 Volume
455 kg mass
Electrical Systems:
P= 1,000,000 watts
R= 1e-10 ohms
I= 100000000 amps
E= 0.01 V
Your Inputs:
Distance from Impact: 3000.00 km = 1863.00 miles
Projectile Diameter: 0.10 m = 0.33 ft = 0.00 miles
Projectile Density: 8000 kg/m3
Impact Velocity: 74.42 km/s = 46.22 miles/s
Impact Angle: 90 degrees
Target Density: 1500 kg/m3
Target Type: Crystalline Rock
Energy:
Energy before atmospheric entry: 1.16 x 1010 Joules = 0.28 x 10-5 MegaTons TNT
The average interval between impacts of this size somewhere on Earth is less than 1 month.
Atmospheric Entry:
The projectile lands intact, with a velocity 0.05 km/s = 0.03 miles/s.
The energy lost in the atmosphere is 1.16 x 1010 Joules = 0.28 x 10-5 MegaTons.
Major Global Changes:
The Earth is not strongly disturbed by the impact and loses negligible mass.
The impact does not make a noticeable change in the Earth's rotation period or the tilt of its axis.
The impact does not shift the Earth's orbit noticeably.
Crater Dimensions:
What does this mean?
Transient Crater Diameter: 1 m = 4 ft
Transient Crater Depth: 0 m = 1 ft
Final Crater Diameter: 1 m = 5 ft
Final Crater Depth: 0 m = 1 ft
The crater formed is a simple crater
The floor of the crater is underlain by a lens of broken rock debris (breccia) with a maximum thickness of 0 m = 0 ft.
At this impact velocity ( < 12 km/s), little shock melting of the target occurs.
Thermal Radiation:
What does this mean?
At this impact velocity ( < 15 km/s), little vaporization occurs; no fireball is created, therefore, there is no thermal radiation damage.
Seismic Effects:
What does this mean?
The Richter Scale Magnitude for this impact is less than zero; no seismic shaking will be felt.
Ejecta:
What does this mean?
Most ejecta is blocked by Earth's atmosphere
I have to warn you the following is a lot of loose scribbling on my part. I was hoping any of you rail gun enthusiasts out there who have a penchant for physics might tell me what you think. If I don’t get to much flak out of character then I’ll RP the development and eventual launch of my fully automatic mini-rail gun.
The purpose of this weapon is more physiological then anything but don’t kid yourself with enough ammunition this thing will kick your ass. It’s a next step against missile shields, but as it stands its vulnerability to anti satellite warfare makes it a first strike weapon only. But again if you can put a missile shield up over your country I can put on my satellite. Thoughts? Comments?
(7) v(muz)=(2DF/m)^.5=(2DILB/m)^.5=I(2DLu/m)^.5
v(muz)=Muzzle velocity (Meters/Second)
D=Length of rails (Meters)
F=Force applied (Newtons)
m=Mass of projectile (Kilograms)
I=Current through projectile (Amperes)
L=Width between rails (Meters)
B=Magnetic field strength (Teslas)
u=1.26x10^-6 (The magnetic permeability of free space, Henries/Meter)
Mine:
v(muz)= I(2DLu/m)^.5
v(muz)= I(2D(.5m)(1.26*10^-6)/(455kg)^.5
My variable length of the rails D
Current through projectile I
set D to 200m
set I to 100000000 amps
v(muz)=(100,000,000 amps)(2(200m)(.5m)(1.26*10^-6)/(455))^.5
v(muz)=74,420.84m/s
v(muz)=74.42084km/s
Bullet .5m diametre
.065m^3 Volume
455 kg mass
Electrical Systems:
P= 1,000,000 watts
R= 1e-10 ohms
I= 100000000 amps
E= 0.01 V
Your Inputs:
Distance from Impact: 3000.00 km = 1863.00 miles
Projectile Diameter: 0.10 m = 0.33 ft = 0.00 miles
Projectile Density: 8000 kg/m3
Impact Velocity: 74.42 km/s = 46.22 miles/s
Impact Angle: 90 degrees
Target Density: 1500 kg/m3
Target Type: Crystalline Rock
Energy:
Energy before atmospheric entry: 1.16 x 1010 Joules = 0.28 x 10-5 MegaTons TNT
The average interval between impacts of this size somewhere on Earth is less than 1 month.
Atmospheric Entry:
The projectile lands intact, with a velocity 0.05 km/s = 0.03 miles/s.
The energy lost in the atmosphere is 1.16 x 1010 Joules = 0.28 x 10-5 MegaTons.
Major Global Changes:
The Earth is not strongly disturbed by the impact and loses negligible mass.
The impact does not make a noticeable change in the Earth's rotation period or the tilt of its axis.
The impact does not shift the Earth's orbit noticeably.
Crater Dimensions:
What does this mean?
Transient Crater Diameter: 1 m = 4 ft
Transient Crater Depth: 0 m = 1 ft
Final Crater Diameter: 1 m = 5 ft
Final Crater Depth: 0 m = 1 ft
The crater formed is a simple crater
The floor of the crater is underlain by a lens of broken rock debris (breccia) with a maximum thickness of 0 m = 0 ft.
At this impact velocity ( < 12 km/s), little shock melting of the target occurs.
Thermal Radiation:
What does this mean?
At this impact velocity ( < 15 km/s), little vaporization occurs; no fireball is created, therefore, there is no thermal radiation damage.
Seismic Effects:
What does this mean?
The Richter Scale Magnitude for this impact is less than zero; no seismic shaking will be felt.
Ejecta:
What does this mean?
Most ejecta is blocked by Earth's atmosphere